思路：倒序单调栈。弹出所有 ≤ 当前身高的元素（这些人都能被看到），count 为弹出数量；若栈非空，还能看到栈顶（第一个更高的人），故 +1。能看到的人数 = count + (栈非空 ? 1 : 0)。
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"There's a tremendous amount of succession planning happening at the moment. And there is the reality that the pipeline of 'ready-now' CEOs has decreased over the last several years," she says.
His thesis at the Navy Academy was in the unheard-of topic of liquid-fuel engines. After graduation, he hoped to specialise in this pioneering new technology.
Медведев вышел в финал турнира в Дубае17:59